Why Does Bragg's Law Require Integers?

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SUMMARY

Bragg's Law, expressed as 2d sin θ = nλ, necessitates that n be an integer to achieve constructive interference in wave phenomena. If the extra path length of 2d sin θ is not an integer multiple of the wavelength λ, destructive interference occurs, resulting in no observable wave at that angle θ. This principle is fundamental in understanding diffraction and interference patterns in crystallography and wave physics.

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  • Familiarity with Bragg's Law in crystallography
  • Knowledge of sine functions and their application in physics
  • Basic concepts of constructive and destructive interference
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aoner
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Hi there,

So in bragg's law [itex]2d\sin \theta =n\lambda[/itex], n needs to be an integer. Can anyone explain why? I mean, what if the extra path 2d that the 'second beam' has is not dividable by a wavelength?
Not sure if this is asked before but could not find it!

Cheers,
Adnan
 
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If the extra path 2dsinθ is not an integer multiple of the wavelength, then you don't get constructive interference, hence no wave for that angle θ.

img_full_47305.gif
 
Ah, yes! Sorry just also came up with that haha. Thanks!
 

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