Why does (Λ⁻¹)μν equal Λνμ in Lorentz transformations?

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grzz
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During my reading I met with,

-1)μν = Λνμ ≡ ημρΛρσησν.

Is it correct to say that η raises and lowers the indices of Λ giving Λμν, which, in turn, will give (Λ-1)μν = Λμν?

Thanks for any help.
 
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Thanks Dextercioby for your help.
Does that mean that there is a misprint in what I read and the μ and the ν of the η must be exchanged?