Why is Cobalt-60 Radioactive with an n/p Ratio of 1.22?

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Discussion Overview

The discussion centers around the radioactivity of Cobalt-60, specifically addressing the neutron-to-proton (n/p) ratio and its implications for stability and radioactivity. Participants explore theoretical frameworks and rules related to isotopes and their stability, including the Mattauch rule.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that a common rule suggests substances with an n/p ratio greater than 1.56 become radioactive, questioning why Cobalt-60, with an n/p ratio of 1.22, is radioactive.
  • Another participant responds that the n/p ratio is merely a rule of thumb and that Cobalt-60's radioactivity is due to it being energetically favorable for it to be radioactive.
  • A third participant introduces the Mattauch rule, stating that among isotopes with the same mass and differing proton numbers, at least one must be radioactive, while noting exceptions such as Antimony-123 and Tellurium-123, and Tantalum-180 and Hafnium-180.
  • This participant further explains that the only stable isotopes with odd numbers of protons and neutrons are limited to four light isotopes, suggesting that Cobalt-60, being odd-odd and not one of these stable isotopes, must be radioactive.

Areas of Agreement / Disagreement

Participants express differing views on the significance of the n/p ratio and the applicability of the Mattauch rule. There is no consensus on the reasons for Cobalt-60's radioactivity, indicating multiple competing perspectives remain.

Contextual Notes

The discussion highlights the limitations of rules of thumb in predicting radioactivity and the specific conditions under which certain isotopes may be stable or unstable. The implications of the Mattauch rule and its exceptions are also noted, but not resolved.

americast
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I have heard that if n/p ratio of a substance becomes more than 1.56, it becomes radioactive. But for Cobalt-60, n/p= 1.22. Yet it is radioactive. Why is that so?

Thanx in advance...
 
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That is only a rule of thumb.
Co60 is radioactive because it is energetically favorable for it to be so.
 
There is a simple rule named Mattauch rule with just 2 exemptions:

Out of two isotopes with same mass and whose proton number differs by one, at least one must be radioactive.

The 2 exemptions are:
Antimony-123 and tellurium-123 are both stable
Tantalum-180 and hafnium-180 are both stable (Also tungsten-180 decays by alpha decay, not electron capture as it should by Mattauch rule).

A consequence of Mattauch rule is:
By Mattauch rule, the only stable isotopes with odd number of protons and neutrons are the 4 light isotopes D, Li-6, B-10 and N-14. All others should be radioactive.
Tantalum 180 is violating Mattauch rule and so is the 5th stable odd-odd isotope. There are still just these 5. Cobalt 60 is odd-odd, and is not one of these 5 stable isotopes, so it is radioactive.
 
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Thanx a lot...!
 

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