Why is det(V ⊗ V) = 0 for any vector field V?

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Homework Statement


The probem is to show within 10 seconds that Det([tex]\vec{V}[/tex] [tex]\otimes[/tex][tex]\vec{V}[/tex])=0

with [tex]\vec{V}[/tex](x,y,z)=(Vx([tex]\vec{r}[/tex]),Vy([tex]\vec{r}[/tex]),Vz([tex]\vec{r}[/tex]))

The Attempt at a Solution


So I thought if I show the matrix is not invertible I would be done. But even with that I can't easily solve it in a few seconds...

Tips?
 
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You can use the Levi-Civita symbol to write down the determinant. In 3d, this is

[tex]\det A = \sum_{ijk} \epsilon_{ijk} A_{1i} A_{2j} A_{3k}.[/tex]

If you apply this to your dyadic, you should be able to see that it vanishes quickly.