Why is the integration result not -xe^-x - e^-x?

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Discussion Overview

The discussion revolves around the integration of the function \( x e^{-x} \). Participants explore the correct application of integration techniques, particularly integration by parts, and question the resulting expression.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant questions why the integration result is not \(-xe^{-x} - e^{-x}\).
  • Another participant prompts for the result of the integral \(\int x e^{-x} \, dx\), indicating a potential misunderstanding.
  • A later reply suggests that the integration by parts method leads to the result \(-xe^{-x}\) after correcting an earlier miscalculation.
  • Another participant introduces an alternative approach by rewriting the differential equation, suggesting it simplifies the integration process.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the integration result, as there are differing interpretations and methods presented.

Contextual Notes

The discussion includes various assumptions about the integration process and the definitions of the functions involved, which may not be fully articulated.

Cadbury
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View attachment 3778

So v' is the one to be integrated and v is the answer,
why is it not -xe^-x - e^-x ? :confused:

Thank you very much!
 

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Hello Cadbury. What is the result of $$\int x e^{-x} \, dx?$$
 
Fantini said:
Hello Cadbury. What is the result of $$\int x e^{-x} \, dx?$$

Oh, I get it now haha, first I have to use integration by parts where u= x, dv= e^ -x then uv - integral(vdu) then after

-xe^-x +e^-x - e^-x = -xe^-x hehe
 
It's even easier if you write the first DE as $\displaystyle \begin{align*} y' = \left( x - 1 \right) \, \mathrm{e}^{-x} \end{align*}$, you can still apply integration by parts and this time you don't have to do two separate integrals...
 

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