Why is the limit at x=0 equal to zero in this calculus problem?

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Homework Help Overview

The discussion revolves around a limit problem in calculus, specifically evaluating the limit as x approaches 0 for an expression involving square roots and fractions. Participants are examining the validity of the expressions and their limits.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the correctness of the original limit expression and its derivation. There is discussion about the implications of the square root becoming negative and the behavior of the limits as x approaches 0. Some participants suggest there may be transcription errors in the problem statement.

Discussion Status

The discussion is active, with participants providing insights into the potential issues with the expressions presented. There is acknowledgment of possible errors in transcription, and some participants are exploring the implications of these errors on the limit evaluations.

Contextual Notes

There is mention of a potential transcription error affecting the limit expressions, which may lead to incorrect conclusions about their behavior as x approaches 0. Participants are encouraged to verify the original problem for accuracy.

SimpliciusH
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I was copying some old text and I came across a limit I didn't understand.

It starts as

[tex]\stackrel{Lim}{x\rightarrow0}\frac{\sqrt{x^2+2-1}-x}{x}[/tex]

and then understandably continues until[tex]\stackrel{Lim}{x\rightarrow0}\frac{x-1}{x*\sqrt{x^2+x-1}+x}=0[/tex]

Why would this be zero? x-1 goes to -1, x goes to zero and anything multiplied by zero is zero. And dividing with zero is a no no...Sorry for the bad format I'm still trying to get a hang of latex.
 
Last edited:
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The second limit has no sense. The expression under the square root becomes negative when x--->0.

ehild
 
ehild said:
The second limit has no sense. The expression under the square root becomes negative when x--->0.

ehild

The second limit is derived from the first one. I know the second one makes no sense but its quite confidently written that it equals zero.

Is the zero perhaps a reference to the first limit? And there was a mistake or typo made during solving?
 
You must have made at least one transcription error.

Your first expression

[tex] \lim_{x \to 0} \frac{\sqrt{x^2+2-1}-x}{x}[/tex]

does not exist - the expression goes to infinity IF what you have beneath the square root is correct.

The second expression

[tex] \lim_{x \to 0} \frac{x-1}{x\,\sqrt{x^2 + x -1} +x}[/tex]

does not equal zero - it too goes to infinity (note that the denominator is

[tex] x \left(\sqrt{x^2+x-1} + 1\right)[/tex]

and this goes to zero as [itex]x[/itex] itself does. More importantly, this does not come from your first expression.

Please examine your original problem and repost.

I could attempt to "guess" different forms for the correct expression, but:
- there is no guarantee would ever hit the correct one, even though I'm reasonably sure I would)
- the weather is fantastic, my bicycle is ready to go, and there is a 55-mile ride mapped out that has my name on it. hoo-rah!
 
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Thanks for taking a look at this. I've found the same problem solved on some other notes I was doing and found the transcript error.
 

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