XeF6 ion: electron geometry, hybridization, and lone pairs

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Neurocscience
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This problem is giving me some trouble:
Check the statements that correctly apply to the XeF6 ion:

a. There is an octahedral electron pair arrangement around Xe
b. The hybridization of Xe is d2sp3
c. The molecular structure is octahedral
d. There is one lone pair on the Xe atom
e. There are no lone pairs on the Xe atom

Could someone please explain it to me?

I know its molecular geometry is distorted octagon and its electron pair geometry is pentagonal bipyramidal. It also has 2 lone electron pairs, right? The hybridization I'm no so sure about...
 
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I don't think it has two lone pair.
The total valence electron is 50. Because there are six F which already bond to the Xe, there is only two electrons left, that is only one lone pair.
 


It has one lone pair and hybridisation is SP3d3...