I have an equation I need to solve by using undetermined coefficients:(adsbygoogle = window.adsbygoogle || []).push({});

y'' - y' = e^{x}

The auxiliary equation is:

r^{2}- r = 0 , so 2 real roots (R_{1}=0, R_{2}= 1)

So, y_{c}(x) = C_{1}+ C_{2}e^{x}

Now for the particular solution:

I can try Ae^{x}but this is already present in the complementary solution. Do I use:

y_{p}(x) = xAe^{x}

Is this the right move at this point in the problem?

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Y'' - y' = e^x [2nd order nonhomogenous diff Eq]

**Physics Forums | Science Articles, Homework Help, Discussion**