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WingZero
Dec4-03, 09:14 PM
pH = -log[H+]

Express the following concentrations in terms of pH.

[H+] = 1 * 10^-5 mol/L

The_Brain
Dec4-03, 10:31 PM
It's right in front of you. You have the molar concentration for [H+], now just plut it into the equation.

-log(10^-5) = pH = 5

Remember: [OH-][H+] = 10^-14

You will probably need this later on. This is where the lograrithmic pH scale comes from and why it "supposedly" goes from 0-14, although you can have negative pH's with strong enough concentrations.

Now maybe you can solve my problem in the thread "balance the equation"! heh