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mustang
Dec18-03, 08:40 PM
Problem 11.
Find the magnitude electric field at a point midway between two charges of 34.4*10^9 C and 78.6*10^-9 C separated by a distance of 58.2 cm. Answer in N/C.
Note: Do i use coulomb's law? If so, when i multiply the constant to the quiotent is that my answer?
Problem 14.
An electron moving through an electric field experiences an acceleration of 6*10^3m/S^2.
a. Find the magnitude of the electric force acting on the electron. Answer in N.
Note: Do i use F=mass*acceleration?
b. What is the magnitude of the electric field strength? Answer in N/C.
What formula do I use?
himanshu121
Dec18-03, 11:36 PM
E=qF will help u
F=ma will do
Originally posted by mustang
Problem 11.
Find the magnitude electric field at a point midway between two charges of 34.4*10^-9 C and 78.6*10^-9 C separated by a distance of 58.2 cm. Answer in N/C.
Note: Do i use coulomb's law? If so, when i multiply the constant to the quiotent is that my answer?
Find the field from 1 then the field from the other then subtract.
field from first charge:
F = \frac{k q_1 q_2}{d^2}
One of the charges isn't there so just divide it out.
\frac{F}{q_1} = \frac{k q_2}{d^2}
\frac{F}{q_1} = \frac{(9x10^9)(34.4x10^-^9)}{0.291^2}
\frac{F}{q_1} = 3656 N/C
field from second charge:
\frac{F}{q_1} = \frac{k q_2}{d^2}
\frac{F}{q_1} = \frac{(9x10^9)(78.6x10^-^9)}{0.291^2}
\frac{F}{q_1} = 8354 N/C
field at that point:
8354 - 3656 = 4698 N/C
Problem 14.
An electron moving through an electric field experiences an acceleration of 6*10^3m/S^2.
a. Find the magnitude of the electric force acting on the electron. Answer in N.
Note: Do i use F=mass*acceleration?
b. What is the magnitude of the electric field strength? Answer in N/C.
What formula do I use?
For question A:
You know the formula F = ma. You know the mass of an electron and its rate of acceleration. Sub in to find the force.
For question B:
The force is given by the field strength x charge. For field I'll just put L since I don't know what it should be.
F = Lq
L = F/q
You solved the force in part A and you know the charge of an electron.
mustang
Dec19-03, 12:37 AM
I rechecked and for problem 11 it was 34.4*10^-9C.
himanshu121
Dec19-03, 02:01 AM
so the answer will be 4698 * 10^-9
mustang
Dec19-03, 04:42 PM
I had a=6*10^3 and m=9.109*10^-31. I subsituted those values for ma in F=ma and got 5.4654*10^-27. When i posted the answer I got it wrong. What did I do wrong?
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