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physicsss
Apr6-06, 04:15 AM
What is the maximum energy a photon of UV light ( lamda= 320 nm) can transfer to an electron in a Compton collision?

I used the Compton eq. and set cos= -1 and found the change in lamda to be 0.00486 nm. then using p=h/lamda where p is the momentum, i found the momentum for when lamda is 320 nm and 0.00486 nm. then I added the two momentums. How do I the energy from here?

Meir Achuz
Apr6-06, 05:47 AM
E=hc/\lambda.
dE=-hc d\lambda/\lambda^2.

Astronuc
Apr6-06, 07:38 AM
For light E = h\nu = pc, where E is energy and p is momentum.