How Do You Integrate Functions Involving Powers and Trigonometric Terms?

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SUMMARY

This discussion focuses on integrating functions involving powers and trigonometric terms, specifically the integral of x^(1/3) divided by (x^(1/3) - 1) and finding the area bounded by the curve y = 2x - tan(0.3x) between x = 1 and x = 4. The integration process involves substitution with u = x^(1/3), leading to the integral of u^3/(u-1) and further decomposition into simpler integrals. Additionally, participants confirm that the area can be found by integrating the function 2x - tan(0.3x) over the specified interval.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with substitution methods in integration
  • Knowledge of trigonometric functions and their properties
  • Ability to evaluate definite integrals
NEXT STEPS
  • Study integration techniques involving substitution and partial fractions
  • Learn about the properties of trigonometric functions in calculus
  • Explore the application of definite integrals in finding areas under curves
  • Review advanced integration techniques, such as integration by parts
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone interested in solving complex integrals involving powers and trigonometric functions.

Blade
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INT x^(1/3) / x^(1/3) -1 dx
u = x^(1/3)
x = u^3
dx = 3u^2du

INT (u/u-1)3u^2du = 3
INT u^3/(u-1) du
INT [u^2 + u + 1/(u-1)]du
Then just integrate each part?

-----------
Find the area of the region bounded.

y=2x - tan(0.3x), x-1, x=4, y=0
Need some guidance where to start here, and how the conditions will be used.
 
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Looks reasonable to me!

What guidance do you need for the second problem?

Just integrate 2x- tan(0.3x) from 1 to 4.
 
Originally posted by Blade
INT x^(1/3) / x^(1/3) -1 dx
u = x^(1/3)
x = u^3
dx = 3u^2du

INT (u/u-1)3u^2du = 3
INT u^3/(u-1) du
INT [u^2 + u + 1/(u-1)]du
Then just integrate each part?

-----------
Find the area of the region bounded.

y=2x - tan(0.3x), x-1, x=4, y=0
Need some guidance where to start here, and how the conditions will be used.

I don't see any ln in the integrand.
 

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