Which cylinder will reach the bottom of the plane first?

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The discussion centers on the dynamics of a solid cylinder versus a hollow cylinder on an inclined plane. The moment of inertia for the solid cylinder is calculated as I_solid=(1/2)MR^2, while for the hollow cylinder, it is I_hollow=MR^2. Due to the lower moment of inertia, the solid cylinder experiences less resistance to rotational motion, allowing it to reach the bottom of the plane first. This conclusion is based on the principles of rotational dynamics and inertia.

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ksle82
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Please check if my answer is reasonable. Any input is appreciated.

Q. Given a hollow and a solid cylinder of equal masses that are placed on an inclined plane. Also, both cylinders have equal radii. Which cylinder will rewach the bottom of the plane first?

Solution:
I_solid=(1/2)MR^2
I_hollow=MR^2 (fow negligible thickness cylinder)

-I about an axis is used to describe how difficult it is to induce rotational motion. Higher I means higher resistance to rotational motion, and vice versa. Therefore, the solid cylinder reaches the bottome first.
 
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Seems like the solid one should reach the bottom first because it more easily rotates. Don't think you posted in the right section though.
 

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