electric circuit

[teng125]

http://www.savefile.com/files/7288537

find the current I(B) by calculation

Use the current function and KVL
the function is given as I(B)=0.01 (V(B) - 0.65V)^2

Can somebody pls show me the KVL ??
i tried to write the KVL as V(i) - I(B)R(i) - V(B) =0
then substitute into the function but doesn't work.

pls help
thanx

[berkeman]

The attachment didn't work for me -- all I got was some pop-up ads and the Savefile home page or something. Can you upload it or post it somewhere else?

[teng125]

http://www.sendspace.com/file/s0utj1

try this pls

thanx

[berkeman]

Still lots of popus and no circuit diagram. Try saving it as a pdf or jpg and uploading it to PF. If you need a free PDF writer, to to PrimoPDF.com.

[teng125]

nono,just download the file.there is a link at the bottom which u need to click on it to download

i have tried

[doodle]

What is the answer?

[teng125]

the answer is 2.781mA
Can u solve it??
pls teach me...
thanx very much

[teng125]

sorry,actually it is given that I(c) = 150 I(B)
so the answer for the I(c) is 2.781mA

[berkeman]

nono,just download the file.there is a link at the bottom which u need to click on it to download

i have tried
Ahhh, click the link next to the red flashing arrow thing. Got it. What are the values of Vi, Ri, Vo and R? You need those to get anywhere with the calculation. And where did that equation come from that you gave in your first post?

Use the current function and KVL
the function is given as I(B)=0.01 (V(B) - 0.65V)^2

[teng125]

the equation is given in the answer.anyway,how do u write the KVL loop eqn??
i just want to know how do u write it pls

thanx

[Meson]

Your equation describing the loop is perfect and it works. Please tell us in detail in what way does it not work for you?

EDIT:
You meant

I_{B}(V_{B})=0.01\frac{A}{V^2}(V_{B}-0.65V)^2

right?

[doodle]

Unless I am missing something here, I don't think you can find a value for IB unless you know the values of Vi, Ri and the rest.

Please state the question in full.

[teng125]

okok.....i have the values

thank you