How much total kinetic energy is needed in this case?

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Homework Help Overview

The discussion revolves around a physics problem involving particle collisions in a particle accelerator, specifically the production of a new particle X through the collision of positrons and electrons. The problem includes calculating the energy required for these collisions, considering both a stationary electron and a scenario where both particles collide with equal velocities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy and momentum principles but expresses difficulty in achieving a solution. Some participants suggest using Einstein's equation and considering the center of mass frame for analysis. Others discuss the relevance of different mass definitions in the context of relativistic physics.

Discussion Status

The discussion is ongoing, with participants providing guidance on relevant concepts and suggesting different approaches to the problem. There is no explicit consensus on a single method, and multiple interpretations of the problem are being explored.

Contextual Notes

The problem involves specific values for the resting mass of the particles and the energy required for the reactions, which may influence the calculations. The original poster expresses a desire for understanding rather than just a solution.

eri3an
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I have a problem with an exercise from school. could anyone help me?

Let say that you are searching for a new particel X by making collison between positrones and elektrones in an particelaccelerator. you guess that the new particles resting mass is 210 MeV/c^2 and you hope to produce it by:

(e+) + (e–) ---> X + photons

a) Let us say that the electron (e-) is in resting state in the laboratory system. How much energy is needed to accerate positrons (e+) to such a velocity for the reaction to take place?

b)On less energy demanding way of doing it is to let e+ och e– collide with each other from opposite directions with the same velocity How much total kinetic energy is needed in this case?

resting mass for an electrone or positron is 0.511 MeV/c^2

please I'm not interested in just getting an answer how do i solve it? I've tried by deriving from the E(a) + E(b) = E(c) + E(d) and tried to go using conservation of momentum but it doesn't seem to work :( Maybe I'm out on bad ice?
 
Last edited:
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Hi eri3an,
you must remember Einstein's equation : E = mc^2, where m is the mass of the particle when it is moving.
 
eri3an said:
I have a problem with an exercise from school. could anyone help me?

Let say that you are searching for a new particel X by making collison between positrones and elektrones in an particelaccelerator. you guess that the new particles resting mass is 210 MeV/c^2 and you hope to produce it by:

(e+) + (e–) ---> X + photons

a) Let us say that the electron (e-) is in resting state in the laboratory system. How much energy is needed to accerate positrons (e+) to such a velocity for the reaction to take place?

b)On less energy demanding way of doing it is to let e+ och e– collide with each other from opposite directions with the same velocity How much total kinetic energy is needed in this case?

resting mass for an electrone or positron is 0.511 MeV/c^2

please I'm not interested in just getting an answer how do i solve it? I've tried by deriving from the E(a) + E(b) = E(c) + E(d) and tried to go using conservation of momentum but it doesn't seem to work :( Maybe I'm out on bad ice?

I suggest you to study the problem in the CM (centre of mass) system.
Then you can pass to the system of the laboratory by Lorentz transformations.
 
borisleprof said:
Hi eri3an,
you must remember Einstein's equation : E = mc^2, where m is the mass of the particle when it is moving.

i just though this statement could use some elaboration:
[tex]E=\gamma m_0c^2=\sqrt{m_0^2c^4+p^2c^2}[/tex]

i think using the real mass, i mean the thing you divide the force with to get the accelaration is better (and that's what borisleprof did).
but in most textbooks, they talk about the mass you measure at the rest frame...
 
Last edited:

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