PDA

View Full Version : The Horizontal Distance


eureka360
Oct17-06, 05:35 AM
hi guys.. could you please explain why 2.0x10^1 meters is the answer of the horizontal distance between the log and the bridge when the stone is dropped from rest from a 75-m-high bridge and lands on the log as it passess under the bridge if the log moves with a constant speed of 50 meters per second?

gunblaze
Oct17-06, 05:41 AM
Are you sure the answer is 20 meters? Its either ur answer is wrong or that the log is travellin at a speed too fast in water!

radou
Oct17-06, 06:03 AM
hi guys.. could you please explain why 2.0x10^1 meters is the answer of the horizontal distance between the log and the bridge when the stone is dropped from rest from a 75-m-high bridge and lands on the log as it passess under the bridge if the log moves with a constant speed of 50 meters per second?

Doesn't sound right. From the equation of the displacement of the stone y = 75 - \frac{1}{2}gt^2 you can obtain the time it takes to fall down, by setting y equal to zero and solving for t. Further on, use that time to obtain the distance of the log at the moment just before the stone is dropped.

gunblaze
Oct17-06, 06:12 AM
well. The answer should be approximately 200 if the values given are correct. Or else, there may be some error in the question.

radou
Oct17-06, 08:12 AM
well. The answer should be approximately 200 if the values given are correct. Or else, there may be some error in the question.

Yes, it's near 200 [m].

eureka360
Oct17-06, 07:33 PM
the log is travelling 50 meters per second.. yeah i think its 200 meters..ok.. i got it.. thanks guys...