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Harmony
Oct22-06, 02:58 AM
A person stands at the base of a hill that is a straight incline making an angle x with the horizontal. For a given initial speed v, at what angle y (to the horizontal) should objects be thrown so that the distance d they land up the hill is as large as possible?

I realise that tan x = vertical displacement/horizontal displacement, and d^2=horizontal distance^2+vertical distance^2. But no matter how do I manipulate the equation, it seems that I can't get rid of the variable t. Any help would be aprreciated.

Dorothy Weglend
Oct22-06, 03:51 AM
You don't say enough about what you have done for me to figure out where you are in solving this problem.

The objects will follow a parabolic trajectory (I'm sure you know this). So perhaps starting with that would be a good first step.

Dorothy

Hootenanny
Oct22-06, 04:11 AM
If you write your usual equations for your horizontal(dx) and vertical(dy) components in you should have something of the form;

d_{x}=v_{i}\cos(x)t

Do the same for your vertical component. You now have two functions of time. Also note that;

d_{x}=d\cos(y)

and

d_{y}=d\sin(y)

You should then equate the appropriate formulae and then manipulate your horizontal displacement into some of the form t=.... Can you go from here and figure out the last step yourself?