efficiency of a heat engine ?

[cowgiljl]

when i am calculating the eggiciency of a heat engine i have to convert the celicus to kelvis and used this formula

eff = 1-(T cold/T hot)*100

fro example 302C = 593K 610C = 883K

eff = 1-593/883 = about 32.8% efficient

right ?

thanks joe

[Doc Al]

Originally posted by cowgiljl
eff = 1-(T cold/T hot)*100
You mean: eff = [1-(T cold/T hot)]*100.

This is the efficiency of an ideal (reversible) heat engine; real engines will be less efficient.

...
eff = 1-593/883 = about 32.8% efficient

Right.

[Tom Mattson]

Originally posted by cowgiljl
fro example 302C = 593K


Nope, 302+273=575.

[cowgiljl]

it was 320 not 302 but thanks

[Doc Al]

Originally posted by Tom
Nope, 302+273=575.
Good catch, Tom. [:)]