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indigojoker
Jan28-07, 09:30 PM
Please check my work for the following problem:

The problem statement, all variables and given/known data

By subsituting A(r) = c \phi(r) in Gauss's and Stokes theorems, where c is an arbitrary constant vector, find these two other "fundamental theorems":

a) \int_{\tau} \nabla \phi d \tau = \int_{S} \phi ds
b) - \int_{S} \nabla \phi \times ds = \int_{C} \phi dl

The attempt at a solution

So I start with 'a' and I'll subsitute: A(r) = c \phi(r)

Original equation:
\int_{\tau} (\nabla \cdot A) d \tau = \int_{S} A \cdot ds
Subsitution:
\int_{\tau} (\nabla \cdot c \phi) d \tau = \int_{S} c \phi \cdot ds
c \int_{\tau} (\nabla \cdot \phi) d \tau = c \int_{S} \phi \cdot ds
this leads us back to the equation that we want:
\int_{\tau} \nabla \phi d \tau = \int_{S} \phi ds

right?

So I start with 'b' and I'll subsitute: A(r) = c \phi(r)


Original equation:
\int_{s} (\nabla \times A) \cdot ds = \int_{C} A \cdot dl
Subsitution:
\int_{s} (\nabla \times c \phi) \cdot ds = \int_{C} c \phi \cdot dl
\int_{s} \nabla \cdot ( c \phi \times ds) = c \int_{C} \phi \cdot dl

i am stuck here on what to do for part b.

HallsofIvy
Jan29-07, 08:45 AM
Are you aware that
\nabla \times c\phi= c (\nabla \times \phi)?