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mkienbau
Jan31-07, 05:39 PM
1. The problem statement, all variables and given/known data
Find the power series:
e^x arctan(x)

2. Relevant equations

e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!}

arctan(x) = 0 + x - \frac{x^3}{3} + \frac{x^5}{5} - \frac{x^7}{7}
3. The attempt at a solution

So do I multiply 1 by 0, x by x and so forth? Or do I go 1 by 0, 1 by x? Or is there another way?

dimensionless
Jan31-07, 06:07 PM
You have to multiply 1 by the whole acrtan series, x by the whole arctan series, and so on. There might be a way to simplify it though. Wikipedia has this under "power series"

f(x)g(x) = \left(\sum_{n=0}^\infty a_n (x-c)^n\right)\left(\sum_{n=0}^\infty b_n (x-c)^n\right)

= \sum_{i=0}^\infty \sum_{j=0}^\infty a_i b_j (x-c)^{i+j}

= \sum_{n=0}^\infty \left(\sum_{i=0}^n a_i b_{n-i}\right) (x-c)^n

mkienbau
Jan31-07, 07:36 PM
So I kind of treat it like F.O.I.L.?

Tom Mattson
Jan31-07, 07:39 PM
Sort of. FOIL is the distrubutive law for (binomial)X(binomial). Here, you've got two infinitely long "polynomials". Obviously, you won't be able to write out all of the terms. :tongue:

mkienbau
Jan31-07, 08:35 PM
Awesome, I think I got it, I only had to take it out to the x^5 term.