equilibrium problem

[oxide]

PCl5 <---> PCl3 + Cl2
all are gases

PCl5 is 45% decomposed
if .110 mol of PCl5 is put in a 1.00 L container, what will
be the equilibrium concentrations of PCl5, PCl3, and Cl2?

PCl5 = .110 * .45 = .0495
.110-.0495= .0605 mol/L

so I've got .0605 mol/L for all 3 since all have the
same coeff. Is this how to solve?

[thunderfvck]

0.110 - 0.0495 = 0.0605

So there's 0.0605 mol of PCl5, but how much PCl5 reacted? Therefore how much product was formed?

[oxide]

.0495 mol of PCl3
.0495 mol of Cl2

right?

[thunderfvck]

You got it.