Calculating Velocity of a 10-gram Bullet

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SUMMARY

The discussion focuses on calculating the velocity of a 10-gram bullet fired into a 3.0-kilogram block moving at 30 cm/sec using the principle of conservation of momentum. The relevant equation is m1v1 + m2v2 = m1u1 + m2u2, where m represents mass and v and u represent velocities before and after impact, respectively. The user expresses confidence in solving the problem after receiving this foundational information. This discussion highlights the application of momentum conservation in collision scenarios.

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Hi! I would like to know what equation I would use to figure out this question and why?

A 10-gram bullet is fired into a 3.0-kilograme block, given that the block a velocity of 30 cm/sec. With what velocity was the bullet fired?

Thank you for your answer. [?]
 
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The conservation of momentum:
[tex]m_1v_1 + m_2v_2 = m_1u_1 + m_1u_2[/tex]
So that:
[tex]m_[/tex] - mass of each object
[tex]v_[/tex] - velocity of each object before impact
[tex]u_[/tex] - velocity of each object after impact

Do you need more help or can you figure this out yourself now? :smile:
 
thanx I can figure it out from here.:smile:
 

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