Differentiation

[Air]

Differentiate with respect to x

dy = 3x^2 - 5√x + 1/2x^2
dx

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I don't understand how to differentiate this part: 5√x + 1/2x^2. I think changing it to indices form would be: x^1/5 + (2x)^-2?

How can it be worked out? :confused:

[neutrino]

5\sqrt{x} is not (x)^{\frac{1}{5}}. It is five times (x)^{\frac{1}{2}}.

The last term is a bit ambiguous, the way you've typed it. Is it \frac{1}{2}x^2 or \frac{1}{2x^2}? Anyway, neither cannot be simplified to (2x)^-2.

[Air]

5\sqrt{x} is not (x)^{\frac{1}{5}}. It is five times (x)^{\frac{1}{2}}.

That makes more sense. :biggrin:

The last term is a bit ambiguous, the way you've typed it. Is it \frac{1}{2}x^2 or \frac{1}{2x^2}? Anyway, neither cannot be simplified to (2x)^-2.

It's \frac{1}{2x^2}

[neutrino]

It's \frac{1}{2x^2}

It's then (1/2)(x^-2). (2x)^-2 would be (1/4)(x^-2).

[Air]

It's then (1/2)(x^-2). (2x)^-2 would be (1/4)(x^-2).

Ok. I understand. Thanks for the help. :biggrin: