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Evergreen
Apr1-04, 08:41 PM
One of the beams of an interferometer, as seen in the figure below, passes through a small glass container containing a cavity D = 1.19 cm deep.

http://capa1.physics.sunysb.edu/CAPA/Pictures/gian2450.gif

When a gas is allowed to slowly fill the container, a total of 209 dark fringes are counted to move past a reference line. The light used has a wavelength of 594 nm. Calculate the index of refraction of the gas, assuming that the interferometer is in vacuum.


???????????some help

Doc Al
Apr2-04, 12:32 PM
As you add the gas, since it has an index of refraction greater than that of the empty cavity (assume a vacuum), you are essentially phase shifting the light in that leg of the interferometer. For every λ of shift, you will seen a fringe move past the reference line. To figure this out, you must calculate how much of a shift you get by replacing the vacuum with the gas.

Hint: compare the number of wavelengths in the cavity when it is filled with gas to the number when it is empty (filled with vacuum). Remember that the light passes through the cavity twice.