Mass frame.

[azatkgz]

1. The problem statement, all variables and given/known data

Nucleus A,which has rest mass m_A,collides with nucleus B,which has rest mass m_B.In the laboratory frame,nucleus A has energy E>m_Ac^2
abd nucleus B is stationery.Find the total energy of the system in center of mass frame in terms of m_A,m_B and E.



3. The attempt at a solution

What's the center of mass frame?Is it a frame of nucleus A?

[robphy]

Consider the frame in which the total spatial momentum is zero.

[azatkgz]

Is it a center of two nuclei?

[azatkgz]

Then check my solution.
Velocity of A in labframe is
v=c\sqrt{1-(\frac{m_Ac^2}{E-m_Ac^2})^2}
velocity of center of mass
v_c=\frac{m_Av}{m_A+m_B}

In frame which moves with velocity v_c,nucleus A has velocity

v'_A=\frac{v-v_c}{1-\frac{vv_c}{c^2}}.And nucleus B has velocity v'_B=v_c.So the total energy in this frame is

E'=\gamma(v'_A)m_Ac^2+\gamma(v'_B)m_Bc^2

[azatkgz]

I think from the frame moving with velocity v_c,velocities for A and B arer true.But as seems to me m_Av_A\neq m_Bv_B in this frame.

[azatkgz]

Here I tried another solution:

E'=\sqrt{(E+m_Bc^2)^2-E^2+m_A^2c^4}

[learningphysics]

Here I tried another solution:

E'=\sqrt{(E+m_Bc^2)^2-E^2+m_A^2c^4}

Looks right to me.

[azatkgz]

Thanks very much.

And ,if after colission reaction occurs A+B\rightarrowC+D+Q.m_A+m_B=m_C+m_D+Q.Is it

E'^2=(m_Cc^2+m_Dc^2+Q)^2 ? For E minimum

[learningphysics]

Thanks very much.

And ,if after colission reaction occurs A+B\rightarrowC+D+Q.m_A+m_B=m_C+m_D+Q.Is it

E'^2=(m_Cc^2+m_Dc^2+Q)^2 ? For E minimum

I don't understand. What is the question asking for?

[azatkgz]

Oh,sorry.After collision reaction occurs A+B\rightarrow C+D.Suppose that

m_A+m_B=m_C+m_D+Q.Find the minumum E for reaction to occur?And I think that in center of mass frame after reaction total momentum is zero.

[learningphysics]

Oh,sorry.After collision reaction occurs A+B\rightarrow C+D.Suppose that

m_A+m_B=m_C+m_D+Q.Find the minumum E for reaction to occur?And I think that in center of mass frame after reaction total momentum is zero.

sorry. still a little confused. what does Q represent here?