View Full Version : Show that reaction-diffusion PDE is linear
axeeonn
Apr20-04, 11:24 PM
du/dt = f(u)+D(laplacian*u)
where u=u(x,y,t), D>0, f(u)=a*u
I'm not sure where to start other than substitute f(u) with a*u. Suggestions?
arildno
Apr21-04, 07:29 AM
Rewrite your equation in the form:
L(u)=0, L=d/dt-a-D*Laplacian.
Here, L is called a differential operator that works on the function u.
To show that L is linear, you must show that for any functions U,u , and constants c, b that:
L(c*U+b*u)=c*L(U)+b*L(u)
We have:
L(c*U+b*u)=d/dt(c*U+b*u)-a*(c*U+b*u)+D*Laplacian(c*U+b*u)=
=c*(dU/dt-a*U+D*laplacian(U))+b*(dU/dt-a*U+D*laplacian(U))=
c*L(U)+b*L(u),
as required.
Note that if U and u are both solutions to the original differential equation;
i.e. L(U)=L(u)=0,
the linearity of L implies that any sum of U and u also is a solution.
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