View Full Version : Circular Motion - Wall of death Problem
blackbird2552
Apr5-08, 07:49 PM
1. The problem statement, all variables and given/known data
Total mass = 260 kg
Coefficient of Friction = 1.00
r = 4 m
gmax = 4 g
a) Find the minimum speed to keep the rider on the wall of death.
b) Find the maximum speed inside the wall of death of the motorcycle based on gmax
2. Relevant equations
\mu x (mv^2/r) = mg
Fc = mv^2/r
Gforce = mv^2/r
3. The attempt at a solution
a)
V = \sqrt{ g r / \mu}
V = 6.26 m/s
b)
Gforce = mv2/r
4 = 0.26g x v2 / 4 m
V = 7.84 m/s
I dont know if it is right...
Andrew Mason
Apr5-08, 11:00 PM
1. The problem statement, all variables and given/known data
Total mass = 260 kg
Coefficient of Friction = 1.00
r = 4 m
gmax = 4 g
a) Find the minimum speed to keep the rider on the wall of death.
Correct.
b) Find the maximum speed inside the wall of death of the motorcycle based on gmax
Gforce = mv2/r
4 = 0.26g x v2 / 4 m
V = 7.84 m/s
I dont know if it is right...I can't follow your reasoning. What is the maximum radial (normal to the wall) force (in Newtons)? What is the relationship between that force and the speed of the motorcycle? What is the motorcycle speed needed to achieve that force?
AM
blackbird2552
Apr5-08, 11:13 PM
..what i need to do is find is the maximum speed at which the motorcycle should be going to get the max value of g, that is 4 gs....i don't get how i will calculate it!....what i did is, since Fc = mv^2/r....the gforce = mv^2/r., i had the mass and the radius...i solved it for v....i think i should convert the 4 g to the force in newton that would be the maximum radial (normal to the wall) force (in Newtons)...i don't know how to do that...help?...
blackbird2552
Apr6-08, 01:47 PM
i think i got where i went wrong in the second one
The total force acting when the mass is experiencing 4 gs is
4g = 39.24 m/s2
F = ma
F = 260 kg x 39.24 m/s2 = 10202.4 N
to get the max v
Fc = mv2/r
10202.4 = 260kg x v2 / 4 m
V = underoot 156.96
V = 12.5 m/s
Is this right??...
Andrew Mason
Apr6-08, 07:05 PM
i think i got where i went wrong in the second one
The total force acting when the mass is experiencing 4 gs is
4g = 39.24 m/s2
F = ma
F = 260 kg x 39.24 m/s2 = 10202.4 N
to get the max v
Fc = mv2/r
10202.4 = 260kg x v2 / 4 m
V = underoot 156.96
V = 12.5 m/s
Is this right??...Correct.
AM
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