Integrating Sin

[duki]

1. The problem statement, all variables and given/known data

\int\sin(6\theta) d\theta


2. Relevant equations



3. The attempt at a solution

\int6\cos6\theta

Am I close?

[Feldoh]

If it helps do a u-sub where u=6theta

Or you could think of it like this:

If we take the derivative of \frac{d}{d \theta}(-cos(\theta)) = sin(\theta). That's sort of like the anti-derivative which you seek.

If we take the derivative of \frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta).

So from there it's easy to see that\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}

[duki]

errr...

\frac{-\cos6\theta}{6}

[duki]

thanks :)

[Feldoh]

Yeah looks right^^