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smallphi
Jul5-08, 10:32 PM
I have the following PDE:

\frac{\partial f(r,t)}{\partial t} \, \, \frac{\partial g(r,t)}{\partial r} = \frac{\partial f(r,t)}{\partial r} \, \, \frac{\partial g(r,t)}{\partial t}

By a simple check, I know a solution is f = h(g), where h() is arbitrary function. The Maple PDE solver returns exactly that.

How can I prove, f=h(g) is the ONLY type of solution of that PDE?

Anthony
Jul8-08, 09:39 AM
Your statement is equivalent to

\frac{\partial (f,g)}{\partial (t,\tau)} = 0

smallphi
Jul8-08, 03:05 PM
Thanks!