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The_ArtofScience
Aug7-08, 05:25 PM
I was wondering if anyone can solve this odd problem. Chromium is known to vary in the number of valence electrons and in this case, I would hope it has 6. Lead has 4 and oxygen 6. If you were to draw its Lewis dot structure with Chromium in the middle you would leave out Pb without any filled electrons which is to say, it's left with only a stick figure representing 2 electrons.


How does one go about in solving this problem?

hp-p00nst3r
Aug19-08, 02:02 PM
Shouldn't Lead(II) have 6 valence electrons since that is what gives it the +2 charge?
I'm not quite sure though, maybe someone who knows more can confirm that.

GCT
Aug19-08, 03:04 PM
This compound is ionic in nature.

hp-p00nst3r
Aug19-08, 04:50 PM
Then that would just mean a transfer of 2 electrons from the chromate ion to the lead ion.

Wow. My Chemistry is pretty rusty after a year of not doing it.