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JFonseka
Aug14-08, 09:10 AM
Now in my textbook it shows the following partial derivative solution:

\frac{d}{dx}(3y^{4} + e^{x} sin y) = e^{x} sin y

I thought since it's meant to be the partial derivative in terms of x that the y variable would be untouched.

What's happening?

uman
Aug14-08, 09:18 AM
What's the first derivative of f(x) = 3*(5^4) + e^x * sin(5)?

JFonseka
Aug14-08, 09:22 AM
What's the first derivative of f(x) = 3*(5^4) + e^x * sin(5)?

e^x ?

uman
Aug14-08, 09:23 AM
Try again.

JFonseka
Aug14-08, 09:32 AM
Try again.

Huh? What else can it be, the rest are all constants.

Defennder
Aug14-08, 10:09 AM
If a constant is multiplied to f(x), it doesn't become 1 after differentiating them both.

tiny-tim
Aug14-08, 10:33 AM
Hi JFonseka! :smile:
What's happening?

The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:

JFonseka
Aug14-08, 10:36 AM
Hi JFonseka! :smile:


The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:

I get that bit lol, but I don't get why 3y^4 disappeared,

JFonseka
Aug14-08, 10:40 AM
Nvm I get it now.

JFonseka
Aug14-08, 10:45 AM
Thanks to all who helped

BoundByAxioms
Aug14-08, 12:31 PM
Hi JFonseka! :smile:


The Chain Rule is happening!

d/dx(exsiny) = (d/dx(ex)) siny + ex(d/dx(siny)) :smile:

I think you mean the product rule?

tiny-tim
Aug14-08, 01:23 PM
:redface: oops! :redface:

BoundByAxioms
Aug14-08, 07:39 PM
:wink: