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kid_abraxis
Aug14-08, 11:13 PM
can anyone shed some light on this little monster?

Defennder
Aug14-08, 11:42 PM
What you should do is to use the chain rule. Denote the upper limit of the integral (the limit which itself is an integral) as y(x). Then you should be able to see that dF/dx = dF/dy dy/dx.

kid_abraxis
Aug15-08, 03:37 AM
i'll take a look. ta

HallsofIvy
Aug16-08, 06:29 AM
The general Leibniz' formula is
\frac{d}{dx}\int_{\alpha(x)}^{\beta(x)} F(x,t)dt= \frac{d\beta(x)}{dx}F(x,\beta(x))- \frac{d\alpha(x)}{dx}F(x,\alpha(x))+ \int_{\alpha(x)}^{\beta(x)}\frac{\partial F(x,t)}{\partial x} dt