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afcwestwarrior
Aug19-08, 06:29 PM
2/2x+1

how do i figure this out

afcwestwarrior
Aug19-08, 06:43 PM
is it 1/2 (2x+1)

Feldoh
Aug19-08, 07:58 PM
Solve it by u-substitution where u=2x+1

Astronuc
Aug19-08, 09:42 PM
2/2x+1

how do i figure this out Is that \frac{2}{2x+1}?

Then along the lines of Feldoh's comment, what is the antiderivative or integral of 1/u

or \int\frac{du}{u}