queries
Oct1-08, 04:16 AM
I have learnt that to transform from one space to another, we can use
g(e) = g(p)/f’, where de/dp = f’
Can we use this relation to transform wavefunctions of energy space to momentum space?
If not, why?
If so, that's very strange as E= p^2/2m and dE/dp= p/m and put into
|psi>=exp(iEt/hbar) ==>|psi>= exp(ipt/mhbar)??
g(e) = g(p)/f’, where de/dp = f’
Can we use this relation to transform wavefunctions of energy space to momentum space?
If not, why?
If so, that's very strange as E= p^2/2m and dE/dp= p/m and put into
|psi>=exp(iEt/hbar) ==>|psi>= exp(ipt/mhbar)??