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View Full Version : Scalar Product of a diffrential.


raisin_raisin
Oct8-08, 01:41 PM
Hey, in my text book they keep doing this and I can't follow
for example r.\ddot{}r = 1/2 \ddot{}r^{}^2{}
and r.\dot{}r = 1/2 \dot{}r^2{}.

Can anyone explain this to me? I know I should probably know it.

P.S Can't quite get the dot product to look right apologies.

AKG
Oct8-08, 03:08 PM
(rē)' = 2rr' by chain rule. Or if the r's are supposed to be vector functions:

(r.r)'
= r'.r + r.r' by product rule for dot product
= r.r' + r.r' by commutativity of dot product
= 2r.r'