epkid08
Oct11-08, 05:56 PM
\zeta (s)= \frac{1}{(1-2^{1-s})} \sum_{n=0}^{\infty} \frac {1}{(2^{n+1})} \sum_{k=0}^{n}(-1)^k{n \choose k}(k+1)^{-s}
Is the main problem with trying to prove the hypothesis algebraically boil down to the fact that s is an exponent to a "k" term? Would a derivation of the function that had no k terms to an exponent s, be at all helpful to an algebraic approach to the hypothesis?
Is the main problem with trying to prove the hypothesis algebraically boil down to the fact that s is an exponent to a "k" term? Would a derivation of the function that had no k terms to an exponent s, be at all helpful to an algebraic approach to the hypothesis?