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Operators having Hermitian/Antihermitian part?
afrano
Nov13-08, 11:47 AM
Someone told me that any operator can be decomposed in a Hermitian and Antihermitian part. Is this true? How? By addition?
Fredrik
Nov13-08, 11:52 AM
X=\frac{X+X^\dagger}{2}+\frac{X-X^\dagger}{2}
afrano
Nov13-08, 12:11 PM
Of course!
thanks Fredrik
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