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wikidrox
Jun2-04, 03:44 PM
Please assist me with this

The work done to move a 1.0 C charge from point P to Q is 3.0 * 10^-4J. If the charge starts from rest and has 1.0 * 10^-4J of kinetic energy when it reaches point Q, what must the potential difference be between P and Q?

For this would I use

Work done = kinetic + potential

therefore Potential difference = Work done - kinetic

This seems too simple to be right

HeyHow!
Jun3-04, 04:17 AM
if i remember potential difference has something to do with Volts

Doc Al
Jun3-04, 04:58 AM
Work done = kinetic + potential

therefore Potential difference = Work done - kinetic

Don't confuse potential energy (PE) with potential difference (ΔV). The potential energy of a charge (Q) with respect to point at a lower potential (by ΔV) is PE = QΔV.