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JG89
Mar30-09, 07:46 PM
1. The problem statement, all variables and given/known data
Prove that \lim_{x \rightarrow \infty} exp(-x^2) \int_0^x exp(t^2) dt = 0 .


2. Relevant equations



3. The attempt at a solution

This question is giving me a lot of difficulty. I've tried a lot of different ways to do it, here is a list of ways that I've tried.

1) For t>= 1, we have 0 < exp(-x^2) \int_0^x exp(t^2) dt \le exp(-x^2) \int_0^x t e^(t^2) dt . Letting x tend to infinity, the right side of the inequality tends to 1/2 and so the expression which we wish to find the limit of is bounded and monotonically decreasing, thus it must converge.

2) I've tried approximating e^(t^2) by (1 + t^2/n)^n for large enough n, and then expanding using the binomial theorem and integrating term by term, giving me a polynomial of degree n + 1. We can then find a number m such that x^m > the polynomial in question for large enough x. Then we must find the limit of x^m/e^(x^2) as x tends to infinity. Using the theorem that e^(x^2) becomes infinite of a lower order of magnitude than x^m, we know that this quotient must tend to 0. I'm a bit sketchy about this one because I think m must tend to infinity with x, which complicates things. I think it's best to drop this idea.


3) I figured that the integral of t^(1/n) e^(t^2) for t>=1 decreases monotonically towards e^(t^2) for increasing n, and so if I can show that this integral divided by e^(x^2) tends to 0 for increasing x, then that proves what I want to prove. I've tried integrating it with Mathematica but it starts talking about hypergeometric functions, which I know nothing about so I don't think this is a good approach at all.


Any ideas?

lanedance
Mar30-09, 09:52 PM
hi JG89

not 100% sure how or if this will work but if you let
f(x) = exp(-x^2) \int_0^x exp(t^2) dt

could you try differentiating f(x) and then re-integrating to obtain a simpler expression for your limit?

JG89
Mar30-09, 10:00 PM
Nope. Just tried it, and differentiating and then integrating back again just gives me the same expression. I don't see much manipulation I can do to the derivative so that when I integrate I get a simpler expression back.

Dick
Mar30-09, 10:09 PM
Your limit has the form 0*infinity. Doesn't that suggest using l'Hopital's rule?

JG89
Mar30-09, 10:11 PM
L'Hospital works, but I've never been taught that, so I figure I should be able to do this question without it.

Dick
Mar30-09, 10:21 PM
L'Hospital works, but I've never been taught that, so I figure I should be able to do this question without it.

That's annoying.

JG89
Mar30-09, 10:22 PM
I'm surprised that my calc book (Courant's book) makes no mention of l'hopital's rule. I guess there is no other way to do this then?

Dick
Mar30-09, 10:32 PM
There almost certainly is. But I can't figure out a clever way to side step it right now. You could figure out why l'Hopital is true and then reverse engineer the proof into a specific proof for this problem. But that doesn't seem to be a good use of time. I'm surprised as well you don't have l'Hopital to apply yet. It's seems perfect for it.