View Full Version : differential geometry
halvizo1031
Apr27-09, 09:57 PM
I need help with this problem:
given a cirlce on S^2 of radius p in the spherical metric, show that its area is 2pi(1-cos p)
tiny-tim
Apr28-09, 03:29 AM
Hi halvizo1031! Welcome to PF! :smile:
(have a pi: π and a rho: ρ and try using the X2 tag just above the Reply box :wink:)
given a cirlce on S^2 of radius p in the spherical metric, show that its area is 2pi(1-cos p)
Divide the circular region into ring-shaped slices of thickness ds, and integrate …
what do you get? :smile:
halvizo1031
Apr28-09, 10:06 AM
I'm not sure I understand what you wrote.
tiny-tim
Apr28-09, 10:44 AM
I'm not sure I understand what you wrote.
Divide the circle into rings …
the area of each ring is its thickness times its length (ie its perimeter) …
use the metric to find the length of the perimeter of each ring …
then add up the areas of all the rings :smile:
halvizo1031
Apr28-09, 02:32 PM
ok I'll give that a try. thanks!
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