Ksubc question

[Mag]

2BrF5 ↔ Br2 + 5F2
If we wanted to solve for Kc (Kc=product/reactants) would we assume that the products are on the right side of the equation. In other words would we set it up like this

[BrF5]^2 / [Br2] [F2]^5 or


[Br2][F2]^5 / [BrF5]^2

[Gokul43201]

The latter. Yes, by convention, the RHS contains the products.

By this convention, LHS -> RHS is considered the forward direction/reaction and RHS -> LHS is considered the reverse reaction.

[GCT]

assuming that the latter corresponds to the rate limiting reaction...yes.


-------------
Online help with chemistry
http://groups.msn.com/GeneralChemistryHomework