Kc Calculation for BrF5 ↔ Br2 + 5F2 Reaction

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SUMMARY

The equilibrium constant (Kc) for the reaction 2BrF5 ↔ Br2 + 5F2 is calculated using the formula Kc = [products]/[reactants]. According to established conventions, the products are placed on the right-hand side of the equation, leading to the correct formulation as Kc = [Br2][F2]^5 / [BrF5]^2. This setup reflects the forward direction of the reaction, while the reverse reaction is represented by the opposite arrangement. Understanding this convention is crucial for accurately calculating equilibrium constants in chemical reactions.

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Mag
2BrF5 ↔ Br2 + 5F2
If we wanted to solve for Kc (Kc=product/reactants) would we assume that the products are on the right side of the equation. In other words would we set it up like this

[BrF5]^2 / [Br2] [F2]^5 or


[Br2][F2]^5 / [BrF5]^2
 
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The latter. Yes, by convention, the RHS contains the products.

By this convention, LHS -> RHS is considered the forward direction/reaction and RHS -> LHS is considered the reverse reaction.
 
assuming that the latter corresponds to the rate limiting reaction...yes.


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