camilus
Jul21-09, 04:58 PM
I'm a bit confused as to how to calculate the 2nd chebyshev function.
I know \psi (x) = \sum_{p^k \le x} \ln p
but can someone show me how to expand it? Like, do I use for 2^k, 2, 4, 8, 16, 32... for all the p^k \le x, same with 3, and 4 and so on?
MW gives the example:
\psi (10) = \ln (2520) = 3\ln2+2\ln3+\ln5+\ln7
how would say, \psi (30) be written?
I know \psi (x) = \sum_{p^k \le x} \ln p
but can someone show me how to expand it? Like, do I use for 2^k, 2, 4, 8, 16, 32... for all the p^k \le x, same with 3, and 4 and so on?
MW gives the example:
\psi (10) = \ln (2520) = 3\ln2+2\ln3+\ln5+\ln7
how would say, \psi (30) be written?