Finding the Moment of a Force about a Point

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SUMMARY

The discussion centers on calculating the moment of force about point D using the equation MD = rA/D × F, where Fg is 49N and the distance from A to D is 27.5cm. Participants clarify that the moment can be determined by breaking the radius and force vectors into their components and applying the cross product. The use of trigonometric functions, specifically sine or cosine, is essential to resolve the angle affecting the force's impact on point D. This approach simplifies the calculation process and alleviates initial confusion.

PREREQUISITES
  • Understanding of vector mathematics and cross products
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with moments and forces in physics
  • Basic skills in resolving vectors into components
NEXT STEPS
  • Study vector cross product calculations in physics
  • Learn how to resolve vectors into components using trigonometry
  • Explore examples of calculating moments of force in static equilibrium
  • Review applications of sine and cosine in force resolution
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Students in physics, engineering, or mechanics who are learning about moments of force and vector analysis will benefit from this discussion.

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Homework Statement



I need to find the moment of A about D. We are given the Fg on the object to be 49N and the distance from A to D is 27.5cm. I've attached a drawing to help demonstrate.


Homework Equations



MD= rA/D X F

The Attempt at a Solution



I know the radius between A and D is 27.5cm but I'm not sure how to find out how much of the force is actually acting on D! I know I need to use sin or cos of a deduced angle (15 degrees or one relating to that). I'm not sure which trig operation or angle to use.

Would anyone be able to shed some light on how to go about? Much thanks.
 

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sdoug041 said:

Homework Statement



I need to find the moment of A about D. We are given the Fg on the object to be 49N and the distance from A to D is 27.5cm. I've attached a drawing to help demonstrate.


Homework Equations



MD= rA/D X F

The Attempt at a Solution



I know the radius between A and D is 27.5cm but I'm not sure how to find out how much of the force is actually acting on D! I know I need to use sin or cos of a deduced angle (15 degrees or one relating to that). I'm not sure which trig operation or angle to use.

Would anyone be able to shed some light on how to go about? Much thanks.

Welcome to the PF. The equation that you wrote is a vector equation, so you only need to write the vectors r and F, and take their cross product. The definition of the cross product includes the trig function that you need to use. Does that help?
 
Muchly appreciated I understand right now. Simply break the radius and force vector into it's components and cross. I knew it was easier than I thought; my frustration was unjustified!

Thanks man.
 

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