Show that if a is any m x n matrix, then ImA = A and AIn = A

[nietzsche]

1. The problem statement, all variables and given/known data

Show that if A is any m x n matrix, then the m x m identity multiplied by A = A, and A multiplied by the n x n identity = A.

2. Relevant equations



3. The attempt at a solution

I know how to prove this by writing out a general m x n matrix, and multiplying it by the identity, but is there a better way of showing this? It just seems kind of silly when I write it out...

[nietzsche]

http://mathrefresher.blogspot.com/2007/02/identity-matrix.html

just found this, it looks like there is not much else to it...

[JG89]

I can`t really think of another way. The cleanest way I can think of:

(AI)_{i,j } = \sum_{r= 1}^n A_{i, r} I_{r, j} = a_{i, j}