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morr485
Oct29-09, 10:36 PM
1. Verify this identity: a*sin Bx + b*cos Bx = sqrt(a^2 + b^2)sin(Bx + C)
where C= arctan b/a



[b]2. a/sqrt(a^2+b^2)sin Bx + b/sqrt(a^2+b^2)cos Bx=cos C sin Bx + sin C cos Bx=



[b]3.a*sin Bx + b cos Bx = sqrt(a^2 + b^2) sin(Bx + C)



[b]1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution

danago
Oct30-09, 06:15 AM
First thing that jumps to my mind is to make use of the trig expansion:

R sin(Bx+C)=R(sin(Bx) cos(C)+cos (Bx)sin(C))

morr485
Oct30-09, 02:57 PM
danago thanks for the hint.