View Full Version : Expectation formula in Dirac notation.
david.makcenz
Oct31-09, 03:04 PM
Expectation value of operator A is given by following formula in Dirac notation.
<A> = <x|A|x>
where
A : Operator
<A> : Expectation value of A
|x> : State
Somehow I am unable to convince myself that this formula is true.
Would someone please explain it to me?
Thanks
\langle \hat{A} \rangle = \langle x|\hat{A}|x \rangle = \int \psi_{x}^{"*"} \hat{A} \psi_{x} \,d \tau
This is the expectation value postulate of quantum mechanics.
If the wavefunction \psi_{x} is not an eigenfunction of the operator \hat{A} then the measured value of the observable A is variable. When \psi_{x} is normalized such that
\int \psi_{x}^{"*"}\psi_{x} \,d \tau=1
the expectation value above yeilds the average measurement of all possible measurements of A. (Note that d \tau indicates an integration over all space.) This works because, since \hat{A} is an Hermitian operator, its eigenvectors form an orthonormal basis. It follows that any function can be written as an infinite linear combination of eigenfunctions of \hat{A}.
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