Oscillating pendulum question

[maccha]

1. The problem statement, all variables and given/known data


A simple pendulum has a period T. What is the period if the entire pendulum oscillates 0.59 g downwards? (give answer as a ratio of Tnew/T)


2. Relevant equations

T=2\pi(\sqrt{L/g}

3. The attempt at a solution

I'm so confused about this problem. I actually got the answer in the textbook by putting in (9.8-0.59g) for the new acceleration but I really don't understand why.. it was just trial and error. I don't understand why you can just plug in 0.59g for the new acceleration- isn't this the net acceleration anyways? Would subtracting it result in a net acceleration of 0.41g?

[Delphi51]

the entire pendulum oscillates 0.59 g downwards
Could that be "accelerates" instead of "oscillates"?
If so, it simply reduces the acceleration due to gravity felt by the pendulum. Like riding in an elevator accelerating downward.

[maccha]

Yes, accelerates, sorry my mistake. Okay thank you that helps, but I'm still confused as to why though you can't just use 0.59 g if that is what it is accelerating at?

[Delphi51]

On an elevator standing still your weight would be mg or 9.81*m.
If the elevator was accelerating downward at 1 m/s², you would feel a bit lighter: (9.81 - 1)*m. The acceleration takes away from the regular gravity. On a spacecraft falling at 9.81 m/s² you would feel weightless. The pendulum period is a measure of this remaining gravity.

[maccha]

Ohh okay I was approaching the problem completely wrong.. I didn't realize it said the entire pendulum is accelerated downwards. Thanks for the help!