View Full Version : wavefunction, blackhole
Does a blackhole have a wavefunction?
Sure. Everything "has" a wavefunction. The problem is we don't know it.
Ivan Seeking
Jul5-03, 07:42 AM
Originally posted by jby
Does a blackhole have a wavefunction?
Some Quantum Cosmologists work on [the idea] of a wave function for the entire universe. By this it is also suggested that we don't collapse wave functions: When I look at a gauge, I leap into a superposition of eigenstates. [8)]
Originally posted by Ivan Seeking
When I look at a gauge, I leap into a superposition of eigenstates. [8)]
Or... you just leap into one while your other "you" leaps
into another...[:D]
Ivan Seeking
Jul5-03, 08:36 AM
Originally posted by drag
Or... you just leap into one while your other "you" leaps
into another...[:D]
Which one of me were all of you speaking to? [8)]
[:D]
Originally posted by Ivan Seeking
When I look at a gauge, I leap into a superposition of eigenstates. [8)]
What do you mean?
Originally posted by heumpje
Sure. Everything "has" a wavefunction. The problem is we don't know it.
Why not? What makes it difficult compared to microscopic objects?
If we were to start off a search to develop the wavefunction for a blackhole, what are the conditions must the wavefunction that we will get fulfill?
Ivan Seeking
Jul6-03, 12:32 AM
Originally posted by jby
What do you mean?
I don't know. [:D]
Although I got this directly from Dr. Steve Carlip -
http://www.physics.ucdavis.edu/Text/Carlip.html
- I am not sure if this information is on his web site. Quantum Cosmology sites should have some discussions.
Perhaps someone else can help here?
This pointless post was brought to you by the three stooges smileys [:D] [8)] [s(]
Originally posted by jby
Why not? What makes it difficult compared to microscopic objects?
If we were to start off a search to develop the wavefunction for a blackhole, what are the conditions must the wavefunction that we will get fulfill?
Normally (for microscopic objects that is) we look for eigenstates of the Hamiltonian but a macroscopic object is not in an eigenstate.
Originally posted by heumpje
Normally (for microscopic objects that is) we look for eigenstates of the Hamiltonian but a macroscopic object is not in an eigenstate.
In this quantum case, how do you exactly explain eigenstate? And why doesn't a macroscopic object be in an eigenstate? Can there be any chances that the object be in an eigenstate?
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