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ImAnEngineer
Dec5-09, 07:26 AM
1. The problem statement, all variables and given/known data
Prove that \mathop {\lim }\limits_{(x,y,z) \to (0,0,0) } \frac{xyz}{{x^2+y^2+z^2 }} = 0
using the epsilon-delta method

3. The attempt at a solution
0<|(x,y,z)-(0,0,0)|=\sqrt{x^2+y^2+z^2}<\delta
Now I have to rewrite:
0<\left|\frac{xyz}{{x^2+y^2+z^2 }}-0\right|<\epsilon
So that I find a relationship between epsilon and delta.

This is where I get stuck... I can't figure out how to do that.

This is one of my attempts:
0<\left|\frac{xyz}{{x^2+y^2+z^2 }}-0\right|\leq \left|\frac{xyz}{{x^2}}\right|=\left|\frac{yz}{{x} }\right|

Any help is very much appreciated!

grief
Dec5-09, 04:48 PM
Hint: yz<=1/2*(y^2+z^2)

ImAnEngineer
Dec6-09, 06:32 AM
Then it is easy:

0<\left|\frac{xyz}{x^2+y^2+z^2}-0\right|\leq\left|\frac{xyz}{y^2+z^2}\right|\leq\l eft|\frac{xyz}{2yz}\right|=\left|\frac{x}{2}\right |<\frac{\delta}{2}=\epsilon

How did you come up with: yz<=1/2*(y^2+z^2) ?
(Why is it true at all?)