moon gravity problem

[terpsgirl]

(6.67 x 10 ^-11 N m^2/kg^2) (7.36 x 10^22 kg)
___________________________________________
(1.74 x 10^6m) ^2

simplify:

6.67 x 7.36
___________ x 10^-11=22-6(2) x Nm^2/kg^2 * kg
1.74 ^2 ____________ _____________
(10^6)^2 m^2

16.2 x 1 x 10 ^-13 n/kg



What am I doing wrong??

[AKG]

Have a look at what you wrote, it's impossible to read. Moreover, I have no idea what you're doing, and why. What is the actual question you're trying to answer? Is this simply an error in your computation? If so, I suggest you use a calculator.

[terpsgirl]

This problem was given on a previous test...the problem is written exactly as seen on the actual exam:

Moons gravity is (6.67 x 10 ^-11 N m^2/kg^2) (7.36 x 10^22 kg)
___________________________________________
(1.74 x 10^6m) ^2


I was to simplify and give units....I ended up w/ an incorrect answer and I did all the steps...

[AKG]

1.62 N/kg

Look at the dimensions, you'll see that it ends up being N/kg. Use a calculator, and you'll get a number like:

1.6214559386973180076628352490421

Only keep 3 significant digits and you'll get what I got. Were you allowed to use a calculator? If so, I don't see what was so hard. If not, the question is ridiculous.

[matt grime]

I think we're supposed to comment on:

\frac{(6.67 * 10^{-11})*(7.36*10^{22})}{(1.74*10^{6})^2}

and its simplification to, hopefully, whatever the result of (6.67*7.36)/(1.74)^2 is times 10^{-1}
you appear to have used the 10^{6} in the denominator twice.
note you can't assume that what you type in the white box will come out the same in the finished article; fixed width fonts anyone? plus all spaces are treated equally, I think. click on the pretty tex to see how to do it

[Doc Al]

16.2 x 1 x 10 ^-13 n/kg

What am I doing wrong??
You handled the exponents incorrectly:
10^{-11} * 10^{22} / (10^6* 10^6) = 10^{(22-11)}/10^{12} = 10^{11}*10^{-12} = 10^{-1}.

[BobG]

Specifically, you started off good, then did too much of a good thing.

You started off with 10^ [-11+22-6(2)], which is the right way to handle the exponents ( I think, assuming you meant + instead of =).

Then you subtracted the exponents in the denominator again.